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(a)What current is taken by a 3 kW electric geyser working on 240 V mains?
(b) What size fuse should be used in the geyser circuit?
(a) Given:
Power, P = 3 kW = 3 × 1000 = 3000 W [converted kilowatt to watt by multiplying with 1000]
Potential difference, V = 240 V
Current, I = ?
We know that:
$P=V\times I$
Then, $I=\frac{P}{V}$
$I=\frac{3000}{240}$
$I=12.5A$
Thus, a current of 12.5 A is taken by a 3 kW electric geyser, working on 240 V mains.
(b) The size of the fuse used in the geyser circuit should be 13 A because the rating of the fuse used in an appliance should be slightly more than the normal current drawn through it.
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