A ]Solve the Following :
$1 . 9 + ( -3)$
$2 . -5 + ( -2)$
$3 . 8 + 6$
$4 . -3 - ( -5)$
$5 . 9 - ( -4)$
B ] Write the opposite number of the following numbers.
$1 . 47$
$2 . -21$
$3 . -30$
Given :
We have the some numbers.
To do :
We have to solve as per the operations given in the question and find the resultant numbers.
Solution :
We know that,
$(+) \times (-) = (-)$
$(-) \times (-) = (+)$
A ]
1. $9+(-3) = 9-3 = 6$
2. $-5+(-2) = -5-2 = -(5+2) = -7$
3. $8+6 = 14$
4. $-3-(-5) = -3+5 = 5-3 = 2$
5. $9-(-4) = 9+4 = 13$
B ]
1. opposite of $47$ is $-47$.
2. opposite of $-21$ is $ -(-21) = 21$
.
3. opposite of $-30$ is $-(-30) = 30$.
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