\( \angle \mathrm{A} \) and \( \angle \mathrm{B} \) are supplementary angles. \( \angle \mathrm{A} \) is thrice \( \angle \mathrm{B} \). Find the measures of \( \angle \mathrm{A} \) and \( \angle \mathrm{B} \)
\( \angle \mathrm{A}=\ldots \ldots, \quad \angle \mathrm{B}=\ldots \ldots \)

Given:

\( \angle \mathrm{A} \) and \( \angle \mathrm{B} \) are supplementary angles. \( \angle \mathrm{A} \) is thrice \( \angle \mathrm{B} \).

To do:

We have to find the measures of $\angle A$ and $\angle B$.
Solution:

We know that,

Sum of the measures of two supplementary angles is $180^o$.

Therefore,

$\angle A+\angle B=180^o$

$3\angle B+\angle B=180^o$    (Given \angle A=3\angle B)

$4\angle B=180^o$

$\angle B=\frac{180^o}{4}$

$\angle B=45^o$.

$\angle A=3(45^o)$

$\angle A=135^o$.

The measures of $\angle A$ and $\angle B$ are $135^o$ and $45^o$ respectively.

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Updated on: 10-Oct-2022

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