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An object travels $ 14 \mathrm{m} $ in $ 4 \mathrm{s} $ and then another 16 m in $ 2 \mathrm{s} $. What is the average speed of the object?
Solution:
Distance1 = 14 m; Time1 = 4 s
Distance2 = 16 m; Time2 = 2 s
Total distance travelled = Distance1 + Distance2
= 14 m + 16 m = 30 m
Total time =4 s + 2 s = 6 s
Average speed = Total distance / Total time
= 30 m / 6 s = 5 m/s
So the average speed of object = 5 m/s
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