An integer is chosen at random between 1 and 100. Find the probability that it is :
$ ( i)$ divisible by 8
$( ii) $not divisible by 8

Given: An integer is chosen at random between 1 and 100.

To do: To Find the probability that it is :

$( i)$ Divisible by 8

$( ii)$ Not divisible by 8

Solution:

An integer is chosen at random from 1 to 100

Therefore total number of possible outcomes= 100

Numbers divisible by 8 between 1 to 100, are ,

{8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96}

number of favorable outcomes$=12$

$( i)$Probability of getting a number divisible by $( 8)=\frac{No.\ of\ favourable\ outcomes}{Total\ number\ outcomes}$


                                                                          $=\frac{12}{100}$

                                                                          $=\frac{3}{25}$

$( ii).$ Probability of getting a number nto divisible by $( 8)=\frac{No.\ of\ favorable\ outcomes}{Total\ number\ outcomes}$


                                                                                        $=1-\frac{3}{25}$


                                                                                        $=\frac{22}{25}$
 

Updated on: 10-Oct-2022

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