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An incomplete distribution is given below:
Variable: | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-800 |
Frequency: | 12 | 30 | - | 65 | - | 25 | 18 |
Given:
An incomplete distribution is given. The median value is 46 and the total number of items is 230.
To do:
We have to find the missing frequencies using the median formula.
Solution:
Let $p_1$ and $p_2$ be the missing frequencies.
Median $= 46$ and $N = 230$
$150 + p_1 + p_2 = 230$
$p_1+p_2 = 230 - 150 = 80$
$p_2 = 80-p_1$.....….(i)
Median $= 46$ which lies in the class 40-50
$l = 40, f= 65, F = 42+p_1$ and $h = 50-40=10$
Median $=l+(\frac{\frac{\mathrm{N}}{2}-\mathrm{F}}{f}) \times h$
$46=40+\frac{\frac{230}{2}-(42+p_1)}{65}\times 10$
$46-40=\frac{115-42-p_1}{13}\times2$
$6(13)=(73-p_1)2$
$39=73-p_1$
$p_1=73-39=34$
$p_2 = 80 - 34 = 46$ [From (i)]
The missing frequencies are 34 and 46.
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