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An electric pole casts a shadow of length 20 m at a time when a tree 6 m high casts a shadow of length 8 m. Find the height of the pole.
Given:
Length of the shadow of the electric pole = 20 m,
Height of the tree = 6 m,
Length of the shadow of the tree = 8 m
To find: Here we have to find the height of the pole.
Solution:
Let the height of the pole at that time be = a
Now, we know that:
Shadows of all the objects are proportional to their height. So,
Height of the electric pole : Length of the shadow of the electric pole :: Height of the tree : Length of the shadow of the tree
a : 20 :: 6 : 8
Also,
Product of extremes = Product of means
a $\times$ 8 = 20 $\times$ 6
a $\times$ 8 = 120
a = $\frac{120}{8}$
a = 15 m
So, the height of the pole is 15 m.
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