Among the numbers given which number is the smallest ?
$\frac{3}{5}$, $\frac{2}{3}$, $\frac{22}{7}$,and1.

Given: $\frac{3}{5}$, $\frac{2}{3}$, $\frac{22}{7}$,and1

To find: We have to find among the numbers given which number is the smallest?

Solution:

$\frac{3}{5}$, $\frac{2}{3}$, $\frac{22}{7}$,and1. can be written as$\frac{3}{5}$, $\frac{2}{3}$, $\frac{22}{7}$,and$\frac{1}{1}$.

Let's take LCM of the denominators of the fractions 

LCM of 5, 3, 7, and 1 is 105

So the given fractions can be written as

$\frac{3\times21}{5\times21}$, $\frac{2\times35}{3\times35}$, $\frac{22\times15}{7\times15}$, $\frac{105}{105}$

=$\frac{63}{105}$, $\frac{70}{105}$, $\frac{330}{105}$,$ \frac{105}{105}$

Arranging in ascending order

$\frac{63}{105}$, $\frac{70}{105}$, $\frac{105}{105}$, $\frac{330}{105}$

or $\frac{3}{5}$, $\frac{2}{3}$, 1, $\frac{22}{7}$

Clearly $\frac{3}{5}$ is the smallest of the four fractions given.

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Updated on: 10-Oct-2022

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