$ABCD$ is a square, $AC$ and $BD$ intersect at $O$. State the measure of $\angle AOB$.
Given:
$ABCD$ is a square, $AC$ and $BD$ intersect at $O$.
To do:
We have to determine the measure of $\angle AOB$.
Solution:
We know that,
Diagonals of a square bisect each other at right angles.
Therefore,
$\angle AOB = 90^o$.
The measure of $\angle AOB$ is $90^o$.
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