ABCD is a rectangle. E is a point on AB such that AD $=$ AE. Find x and y.
"
Given :
ABCD is a rectangle.
AD $=$ AE.
To do :
We have to find x and y.
Solution :
ABCD is a rectangle.
$∠A = ∠B = ∠C = ∠D = 90°$
E is a point on AB such that $AD = AE$.
In the triangle ADE,
$AD = AE$
We know that,
Angles opposite to equal sides are equal.
Therefore,
$∠ADE = ∠AED$
$∠ADE + ∠AED + 90° = 180°$
$2∠ADE = 180°-90° = 90°$
$∠ADE = \frac{90°}{2} = 45°$.
$∠ADE = ∠AED = 45°$.
$∠AED + ∠y = 180°$ (Sum of the angles on a straight line is 180°)
$45° + ∠y = 180°$
$∠y = 180°-45° = 135°$
$∠ADE + ∠x = 90°$
$45 + ∠x = 90°$
$∠x = 90°-45° = 45°$
The measures of the angles x and y are 45° and 135°.
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