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A wall of length $10\ m$ was to be built across an open ground. The height of the wall is $4\ m$ and thickness of the wall is $24\ cm$. If this wall is to be built up with bricks whose dimensions are $24\ cm \times 12\ cm \times 8\ cm$, how many bricks would be required?
Given:
A wall of length $10\ m$ was to be built across an open ground.
The height of the wall is $4\ m$ and thickness of the wall is $24\ cm$.
The wall is to be built up with bricks whose dimensions are $24\ cm \times 12\ cm \times 8\ cm$.
To do:
We have to find the number of bricks required.
Solution:
Length of the wall $(l) = 10\ m$
$= 10\times100$
$=1000\ cm$
Height of the wall $(h) = 4\ m$
$= 400\ cm$
Thickness of the wall $(b) = 24\ cm$
Therefore,
Volume of the wall $= lbh$
$= 1000 \times 24 \times 400$
$= 9600000\ cm^3$
Dimensions of each brick $= 24\ cm \times 12\ cm \times 8\ cm$
$= 2304\ cm^3$
Number of bricks required $=\frac{\text { Volume of wall }}{\text { Volume of one brick }}$
$=\frac{9600000}{2304}$
$=4167$ bricks