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A truck travelling at 54 km/h is slow down to 36 km/h in 10 sec. Find the retardation.
Here, initial velocity $u=54\ km/h=54\times\frac{5}{18}\ m/s=15\ m/s$
Final velocity $v=36\ km/h=36\times\frac{5}{18}=10\ m/s$
Time $t=10\ sec.$
Therefore, retardation $a=\frac{v-u}{t}=\frac{10-15}{10}$
$=\frac{-5}{10}$
$=-0.5\ m/s^2$
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