A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of $400\ m$ in $20\ s$. Find its acceleration.

Here, initial velocity $u=0$

Distance traveled by truck $s=400\ m$

Time taken $t=20\ s$

Let $a$ be the acceleration of the truck.

On using the equation of motion, $s=ut+\frac{1}{2}at^2$

$400=0+\frac{1}{2}\times a\times20^2$

Or $400=0+200a$

Or $200a=400$

Or $a=\frac{400}{200}$

Or $a=2\ m/s^2$

Thus, the acceleration of the truck is $2\ m/s^2$.

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Updated on: 10-Oct-2022

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