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A sugar syrup of mass 214.2g contains 34.2g of sugar. Calculate the concentration of sugar in the syrup.
Mass of syrup = 214.2g (given) Mass of sugar in syrup= 34.2g (given) Mass of water in syrup = Mass of syrup - Mass of sugar in syrup = 242.2 - 34.2 =180g The molecular formula of sugar is C12H22O11. Molecular mass of sugar = 12(mass of C) + 22(mass of H) + 11(mass of O) = C12H22O11 = 12(12.01) + 22(1.008) + 11(16.00) = C12H22O11 = 342.30 The molar mass of sugar ⇒ 342 g/mol (rounding off 342.30) No. of moles of sugar (nA) = 34.2 ÷ 342 = 0.1mole No. of moles of water (nB) = 180 ÷ 18 = 10 moles Molarity =0.1 × 1000 ÷ 180 = 0.56 mole
Mole fraction of sugar = nA ÷ (nA + nB) = 0.1 ÷ (0.1 + 10) = 0.009
Thus, the mole fraction of sugar syrup is 0.009.