A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follows: (i) Make a grouped frequency distribution table for this data with class intervals as $ 0.00-0.04
A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city.
To do:
We have to
(i) Make a grouped frequency distribution table for this data with class intervals as \( 0.00-0.04,0.04-0.08 \), and so on. (ii) Find the number of days on which concentration of sulphur dioxide was more than \( 0.11 \) parts per million.
Solution:
(i) The given data is large, so we construct a grouped frequency distribution table of class size 0.04.
This implies,
The class intervals are 0.00 - 0.04, 0.04 - 0.08 and so on.
The data is represented in the grouped frequency distribution table as follows:
Concentration of $SO_2$ (in ppm)
Frequency
0.00-0.04
4
0.04-0.08
9
0.08-0.12
9
0.12-0.16
2
0.16-0.20
4
0.20-0.24
2
Total
30
(ii) The number of days in which the concentration of sulphur dioxide was more than $0.11$ parts per million $= 2+4+ 2$