A student prepared an aqueous solution of CuSO4 in beaker X and an aqueous solution of FeSO4 in beaker Y. He then dropped some iron pieces in beaker X and some zinc pieces in beaker Y. After about 10 hours, he observed that the solution in X and Y respectively appears:

(a) Blue and green. (b) Colourless and pale green. (c) Colourless and light blue. (d) Greenish and colourless.


Correct answer:  (d) Greenish and colourless.

Explanation: 

Reaction in Beaker X: $Fe + CuSO_4(aq) (blue) \rightarrow FeSO_4(aq)(green) + Cu$

Reaction in Beaker Y:

$Zn + FeSO_4(aq) (green) \rightarrow ZnSO4(aq) (colourless) + Fe$

Updated on: 10-Oct-2022

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