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A stone is thrown vertically upwards with a speed of 20 m/s. How high will it go before it begins to fall? $(g=9.8\ m/s^2)$
As given, the initial speed of the stone $u=20\ m/s$
Gravitational acceleration $g=8\ m/s^2$
Final speed $v=0$ [At the maximum height velocity of the stone will be zero]
Let the maximum height will be $h$.
On using the equation of the motion, $v^2=u^2+2gh$
$0=20^2+2\times(-8)\times h$ [As stone is going upward, $g$ will be negative]
Or $0=400-16h$
Or $16h=400$
Or $h=\frac{400}{16}$
Or $h=25\ m$
Therefore, the stone will go $25\ m$ high before it begins to fall.
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