![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
A rhombus has diagonals that measure $6\ cm$ and $8\ cm$. What is its area? How much does each side measure?
Given: A rhombus has diagonals that measure $6\ cm$ and $8\ cm$
To do: To find its area and measure of each side.
Solution:
As given, diagonals of the rhombus $d_{1}=6\ cm$ and $d_{2}=8\ cm$
Area of rhombus $A= \frac{( d_1\times d_2)}{2}$
$= \frac{(6 \times 8)}{2}$
$= \frac{48}{2}$
$= 24\ cm^2$
Side $= \sqrt{( \frac{d_1}{2})^2 + (\frac{d_2}{2})^2}$
$=\sqrt{ ( \frac{6}{2})^2 + (\frac{8}{2})^2}$
$= \sqrt{ 3^2 + 4^2}$
$= \sqrt{ 9 + 16}$
$= \sqrt{ 25}$
$= 5\ cm$
Advertisements