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A pond of depth $20cm$ is filled with water of refractive index $\frac{4}{3}$. Calculate the apparent depth of the pond when viewed normally.
Given,
Refractive index of water = $\frac{4}{3}$
Real depth of pond x = 20 cm
Apparent depth, y = ?
We know that,
$Refractive\ index=\frac{Real\ depth}{Apparent\ depth}\phantom{\rule{0ex}{0ex}}$
$n=\frac{x}{y}$
Substiuting the given values in the expression we get-
$\frac{4}{3}=\frac{20}{y}\phantom{\rule{0ex}{0ex}}$
$y=\frac{20\times 3}{4}\phantom{\rule{0ex}{0ex}}$
$y=15m\phantom{\rule{0ex}{0ex}}$
Hence, the apparent depth of the pond when viewed normally will be 15m.
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