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A ladder $15\ m$ long just reaches the top of a vertical wall. If the ladder makes an angle of $60^o$ with the wall. Find the height of the wall.
Given: A ladder $15\ m$ long just reaches the top of a vertical wall. If the ladder makes an angle of $60^o$ with the wall.
To do: To find the height of the wall.
Solution:
Let height of the wall $=BC$
length of the ladder be $AC=15\ m$
The angle between the ladder and the wall $\angle BCA=60^o$
Angle between ladder and the ground $\angle CAB=90^o−60^o=30^o$
Height of the wall $=BC$
$sin30^o=\frac{BC}{15}$
$\Rightarrow \frac{1}{2}=\frac{BC}{15}$
$\Rightarrow BC=\frac{15}{2}=7.5\ m$
Thus, height of the wall is $7.5\ m$.
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