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A hokey team played 25 match in a season it won 20% of them find the number of match lost
Given: Total number of matches played = 25
matches won by them in the season = 20%
To find: The number of lost matches
Solution:
Number of Matches won = 20 % of Total number of matches played
= $\frac{20}{100} \times 25$
= $\frac{1}{5} \times 25$
= $\frac{25}{5}$
= 5
Number of Matches won = 5
Number of Matches lose = Total number of matches played - Number of Matches won
Number of Matches lose = 25 - 5 = 20
Therefore the number of Matches lost = 20
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