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A force of $10\ N$ acted upon a body and the body moves $10\ m$. Find the work done.
Here given:
Force acted upon the body $F=10\ N$
Displacement $d=10\ m$
Therefore, Work done $W=F\times d$
$=10\ N\times 10\ m$
$=100\ Joule$
Thus, the work done is $100\ Joule$.
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