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A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area $1080m^2$? (If required you can split the tiles in whatever way you want to fill up the corners).
Given:
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm.
The area of the floor$=1080\ m^2$
To do:
We have to find the number of tiles required to cover the floor of area $1080m^2$.
Solution:
Area of a tile $=24\ cm \times 10\ cm=240\ cm^2$
Area of the floor$=1080\ m^2=1080\times(100\ cm)^2$
$=1080\times10000\ cm^2=10800000\ cm^2$
Number of tiles required$=\frac{Area\ of\ the\ floor}{Area\ of\ a\ tile}$
$=\frac{10800000}{240}$
$=45000$
Therefore, $45000$ tiles are required to cover the floor.