A circular park of radius 20m is situated in a colony. Three boys Ankur, Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other. Find the length of the string of each phone.
Given:
A circular park of radius $20\ m$ is situated in a colony. Three boys Ankur, Amit and Anand are sitting at an equal distance on its boundary each having a toy telephone in his hands to talk to each other.
To do:
We have to find the length of the string of each phone.
Solution:
The radius of the circular park $= 20\ m$
Ankur, Amit and Anand are sitting at equal distances from each other.
By joining the points, an equilateral triangle $ABC$ is formed.
Produce $BO$ to $L$ which is the perpendicular bisector of $AC$.
Therefore,
$BL = 20 + 10$
$= 30\ m$ ($O$ is the centroid of $\triangle ABC$)
Let $a$ be the side of $\triangle ABC$
$\Rightarrow \frac{\sqrt{3}}{2} a=30$
$a=\frac{30 \times 2}{\sqrt{3}}$
$a=\frac{60 \times \sqrt{3}}{\sqrt{3} \times \sqrt{3}}$
$a=\frac{60 \times \sqrt{3}}{3}$
$a=20 \sqrt{3} \mathrm{~m}$
Hence the distance between each other is $20\sqrt3\ m$.
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