A car covers a distance of \( 120 \mathrm{kms} \). in 8 hours. What is the time taken by the car with \( 1 \frac{1}{2} \) time of the previous speed to cover a distance of \( 450 \mathrm{kms} \) ?

Given:

A car covers a distance of \( 120 \mathrm{kms} \). in 8 hours.

To do:

We have to find the time taken by the car with \( 1 \frac{1}{2} \) time of the previous speed to cover a distance of \( 450 \mathrm{kms} \).
Solution:

We know that,

$Speed=\frac{Distance}{Time}$

Speed of the car initially $=\frac{120}{8}\ km/hr=15\ km/hr$

\( 1 \frac{1}{2} \) times the speed of the car $=1\frac{1}{2}\times15\ km/hr=\frac{3}{2}\times15\ km/hr=\frac{45}{2}\ km/hr$

Time taken by the car with new speed $=\frac{450}{\frac{45}{2}}\ hr$

$=10\times2\ hr$

$=20\ hr$

Therefore, the car takes 20 hours to cover the distance of 450 km.

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Updated on: 10-Oct-2022

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