A bus is moving at an average speed of $46 \frac{2}{3}$ km/h. How much distance will it cover in $2 \frac{2}{5}$ hours ?
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- Take away:(i) \( \frac{6}{5} x^{2}-\frac{4}{5} x^{3}+\frac{5}{6}+\frac{3}{2} x \) from \( \frac{x^{3}}{3}-\frac{5}{2} x^{2}+ \) \( \frac{3}{5} x+\frac{1}{4} \)(ii) \( \frac{5 a^{2}}{2}+\frac{3 a^{3}}{2}+\frac{a}{3}-\frac{6}{5} \) from \( \frac{1}{3} a^{3}-\frac{3}{4} a^{2}- \) \( \frac{5}{2} \)(iii) \( \frac{7}{4} x^{3}+\frac{3}{5} x^{2}+\frac{1}{2} x+\frac{9}{2} \) from \( \frac{7}{2}-\frac{x}{3}- \) \( \frac{x^{2}}{5} \)(iv) \( \frac{y^{3}}{3}+\frac{7}{3} y^{2}+\frac{1}{2} y+\frac{1}{2} \) from \( \frac{1}{3}-\frac{5}{3} y^{2} \)(v) \( \frac{2}{3} a c-\frac{5}{7} a b+\frac{2}{3} b c \) from \( \frac{3}{2} a b-\frac{7}{4} a c- \) \( \frac{5}{6} b c \)
- The maximum speed of a train is 90 km/h. It takes 10 hours to cover a distance of 500 km. Find the ratio of its average speed to maximum speed?
- Solve the following equations:$(a).\ 2y+\frac{5}{2}=\frac{37}{2}$$(b).\ 5t+28=10$$(c).\ \frac{a}{5}+3=2$$(d).\ \frac{q}{4}+7=5$$(e).\ \frac{5}{2}x=-5$$(f).\ \frac{5}{2}x=\frac{25}{4}$$(g).\ 7m+\frac{19}{2}=13$ $(h).\ 6z+10=-2$ $(i).\ \frac{3l}{2}=\frac{2}{3}$$(j).\ \frac{2b}{3}-5=3$
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