A box contains 90 discs which are numbered from 1 to 90. If one discs is drawn at random from the box, find the probability that it bears a two digit number
Given:
A box contains 90 discs which are numbered from 1 to 90.
One disc is drawn at random from the box.
To do:
We have to find the probability that it bears a two digit number.
Solution:
A box contains discs numbered \( 1,2,3,4, .., 89,90 \).
This implies,
The total number of possible outcomes $n=90$.
Two digit numbers from 1 to 90 are $10, 11, .........., 89, 90$.
Total number of favourable outcomes $=81$.
We know that,
Probability of an event $=\frac{Number\ of\ favourable\ outcomes}{Total\ number\ of\ possible\ outcomes}$
Therefore,
Probability that the disc bears a two digit number $=\frac{81}{90}$
$=\frac{9}{10}$
The probability that it bears a two digit number is $\frac{9}{10}$.
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