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$a^2+b^2=25$ and $ab=12$., then $a+b=?$.
Given: $a^2+b^2=25$ and $ab=12$.
To do: To find $a+b$.
Solution:
As given: $a^2+b^2=25$ and $ab=12$
$( a+b)^2=a^2+b^2+2ab$
$\Rightarrow ( a+b)^2=25+2( 12)$
$\Rightarrow ( a+b)^2=25+24$
$\Rightarrow ( a+b)^2=49$
$\Rightarrow ( a+b)=\pm\sqrt{49}$
$\Rightarrow ( a+b)=\pm7$
Thuus, $a+b=\pm7$.
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