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(7/9)^2 ÷(14/3)^2
Given:
$(\frac{7}{9})^2 ÷(\frac{14}{3})^2$
To do:
We have to find the value of $(\frac{7}{9})^2 ÷(\frac{14}{3})^2$.
Solution:
We know that,
$\frac{a^m}{b^m}=(\frac{a}{b})^m$
$\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times\frac{d}{c}$
Therefore,
$(\frac{7}{9})^2 ÷(\frac{14}{3})^2=(\frac{7}{9}\div \frac{14}{3})^2$
$=(\frac{7}{9}\times\frac{3}{14})^2$
$=(\frac{1\times1}{3\times2})^2$
$=(\frac{1}{6})^2$
$=\frac{1^2}{6^2}$
$=\frac{1}{36}$
Therefore, $(\frac{7}{9})^2 ÷(\frac{14}{3})^2=\frac{1}{36}$.
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