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40% of the passenger from a bus got off at station A, 75% of the remaining got off at station B. If the remaining 12 person were taken to station C, find the original number of passengers
Given: 40% of the passenger from a bus got off at station A, 75% of the remaining got off at station B. If the remaining 12 person were taken to station C.
To do: To find the original number of passengers.
Solution:
Let total passengers be $P$.
At $X=0.4P$
Therefore, remaining$=0.6X$
$Y=0.75( 0.6P)$
$Z=12$
$\Rightarrow 0.4P+0.75(0.6P)+12=P$
$\Rightarrow 0.4P+0.45P+12=P$
$\Rightarrow P=0.85P+12$
$\Rightarrow 0.15P=12$
$\Rightarrow P=\frac{12}{0.15}$
$\Rightarrow P=80$
So, total number of passengers were $80$.
Updated on: 10-Oct-2022
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