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25 circular plates, each of radius $ 10.5 \mathrm{~cm} $ and thickness $ 1.6 \mathrm{~cm} $, are placed one above the other to form a solid circular cylinder. Find the curved surface area and the volume of the cylinder so formed.
Given:
25 circular plates, each of radius \( 10.5 \mathrm{~cm} \) and thickness \( 1.6 \mathrm{~cm} \), are placed one above the other to form a solid circular cylinder.
To do:
We have to find the curved surface area and the volume of the cylinder so formed.
Solution:
Radius of each circular plate $r =10.5\ cm$
Thickness of each circular plate $h = 1.6\ cm$
Height of 25 plates placed one above the other $H= 1.6 \times 25$
$= 40\ cm$
Curved surface area of the cylinder so formed $= 2 \pi rH$
$= 2 \times \pi \times 10.5 \times 40$
$= 840 \pi$
$=840\times\frac{22}{7}$
$=120\times22$
$=2640\ cm^2$
Volume of the cylinder $=\pi r^2 H$
$=\pi \times (10.5)^2\times 40$
$= \frac{22}{7}\times110.25\times40$
$= 13860\ cm^3$
The curved surface area and the volume of the cylinder so formed are $2640\ cm^2$ and $13860\ cm^3$ respectively.