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Number is divisible by 29 or not in C++
It's a straightforward problem. We can use the modulo (%) operator to check whether the given number is divisible by 29 or not. Let's see some examples.
Input
29 254
Output
1 0
Algorithm
Implementation
Following is the implementation of the above algorithm in C++
#include <bits/stdc++.h> using namespace std; bool isDivisibleBy29(long long n) { return n % 29 == 0; } int main() { cout << isDivisibleBy29(29) << endl; cout << isDivisibleBy29(234567876543) << endl; cout << isDivisibleBy29(234567657329) << endl; return 0; }
Output
If you run the above code, then you will get the following result.
1 1 0
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