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Node.js – util.types.isGeneratorFunction() Method
The util.types.isGeneratorFunction() method checks whether the passed value is a generator function or not. If the above condition holds, it returns True, else False. The return value may differ from the original source code if a transpilation tool is used.
Syntax
util.types.isGeneratorFunction(value)
Parameters
- value − This input value takes input for the required parameter and checks if it's a Generator function or not.
It returns True or False based upon the input value passed.
Example 1
Create a file with the name "isGeneratorFunction.js" and copy the following code snippet. After creating the file, use the command "node isGeneratorFunction.js" to run this code.
// util.types.isGeneratorFunction() Demo Example
// Importing the util module
const util = require('util');
// Passing a normal function
console.log("1." + util.types.isGeneratorFunction(function foo() {}));
// Passing a generator function
console.log("2." + util.types.isGeneratorFunction(function* gen() {}));Output
C:\home
ode>> node isGeneratorFunction.js 1.true 2.false
Example 2
// util.types.isGeneratorFunction() Demo Example
// Importing the util module
const util = require('util');
var gen = function* id() {
var index = 0;
while (true)
yield index++;
}
// Passing a generator function
console.log("1." + util.types.isGeneratorFunction(gen));
var fn = function f() {
console.log('Welcome to TutorialsPoint !')
}
// Passing a normal function
console.log("2." + util.types.isGeneratorFunction(fn));Output
C:\home
ode>> node isGeneratorFunction.js 1.true 2.false
Updated on: 17-Aug-2021
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