MySQL query to return the count of only NO values from corresponding column value

Let us first create a table −

mysql> create table DemoTable1829
     (
     Name varchar(20),
     isTopper ENUM('YES','NO')
     );
Query OK, 0 rows affected (0.00 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable1829 values('Chris','yes');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1829 values('David','yes');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1829 values('Mike','no');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1829 values('David','yes');
Query OK, 1 row affected (0.00 sec)

Display all records from the table using select statement −

mysql> select * from DemoTable1829;

This will produce the following output −

+-------+----------+
| Name  | isTopper |
+-------+----------+
| Chris | YES      |
| David | YES      |
| Mike  | NO   |
| David | YES      |
+-------+----------+
4 rows in set (0.00 sec)

Here is the query to return the count of only NO values −

mysql> select Name,sum(isTopper='no')
     from DemoTable1829
     group by Name;

This will produce the following output −

+-------+--------------------+
| Name  | sum(isTopper='no') |
+-------+--------------------+
| Chris |                  0 |
| David |                  0 |
| Mike  |                  1 |
+-------+--------------------+
3 rows in set (0.00 sec)