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Multiply a given Integer with 3.5 in C++
To get the result of n * 3.5 we need to calculate (n * 2) + n + (n / 2). Moving the bits to left by 1 will give you n * 2 and moving the bits to right by will you n / 2. Add those to get the result.
n * 3.5 = (n * 2) + n + (n / 2)
You can submit different values of n to verify the above equation. Let's see some examples.
Input
2 7 10
Output
7 24 35
Algorithm
- Initialise the number n.
- Find the n * 2 using left shift bitwise operator
- Find the n / 2 using right shift bitwise operator.
- Add both the above values along with n to get the result.
- Return the result.
It's a straightforward problem with the above steps.
Implementation
Following is the implementation of the above algorithm in C++
#include <bits/stdc++.h>
using namespace std;
int getTheResult(int x) {
return (x << 1) + x + (x >> 1);
}
int main() {
int n = 10;
cout << getTheResult(n) << endl;
return 0;
}Output
If you run the above code, then you will get the following result.
35
Updated on: 25-Oct-2021
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