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Middle of three using minimum comparisons in C++
In this section, we will see how to find the middle of three given values by comparing them. So if three numbers are given like (10, 30, 20), then it will find 20 as this is the middle element. Let us see the algorithm first, then we will implement that algorithm into C++ code.
Algorithm
middle_of_three(a, b, c): Input: Three numbers a, b and c Output: The middle of these three Begin if a > b, then if b > c, then return b else if a > c, then return c else return a else if a > c, then return a else if b > c, then return c else return b End
Example
#include <iostream>
using namespace std;
int mid_three(int a, int b, int c) {
if (a > b) {
if (b > c)
return b;
else if (a > c)
return c;
else
return a;
} else {
if (a > c)
return a;
else if (b > c)
return c;
else
return b;
}
}
main() {
int a = 10, b = 30, c = 20;
cout << "Middle Out of Three "<< mid_three(a, b, c);
}Output
Middle Out of Three 20
Updated on: 30-Jul-2019
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