![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Maximize the number of segments of length p, q and r in C++
Problem statement
Given a rod of length L, the task is to cut the rod in such a way that the total number of segments of length p, q and r is maximized. The segments can only be of length p, q, and r
If l = 15, p = 2, q = 3 and r = 5 then we can make 7 segments as follows −
{2, 2, 2, 2, 2, 2, 3}
Algorithm
We can solve this problem using dynamic programming
1. Initialize dp[] array to 0 2. Iterate till the length of the rod. For every i, a cut of p, q and r if possible is done. 3. Initialize ans[i+p] = max( ans[i+p], 1 + ans[i]), ans[i+q] = max(ans[i+q], 1 + ans[i]) and ans[i+r] = max(ans[i+r], 1 + ans[i]) for all the possible cuts. 4. ans[i] will be 0 if a cut at i-th index is not possible. ans[l] will give the maximum number of cuts possible
Example
#include <bits/stdc++.h> using namespace std; int getMaximumSegments(int l, int p, int q, int r){ int dp[l + 1]; memset(dp, -1, sizeof(dp)); dp[0] = 0; for (int i = 0; i <= l; ++i) { if (dp[i] == -1) { continue; } if (i + p <= l) { dp[i + p] = max(dp[i + p], dp[i] + 1); } if (i + q <= l) { dp[i + q] = max(dp[i + q], dp[i] + 1); } if (i + r <= l) { dp[i + r] = max(dp[i + r], dp[i] + 1); } } return dp[l]; } int main(){ int l = 15, p = 2, q = 3, r = 5; cout << "Number of segments = " << getMaximumSegments(l, p, q, r) << endl; return 0; }
Output
When you compile and execute the above program. It generates the following output−
Number of segments = 7
Advertisements