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Look at the figures and write 's' or ' $ > $ ', '- ' between the given pairs of fractions.
![](/assets/questions/media/153848-1654782451.png)
(a) $ \frac{1}{6} \square \frac{1}{3} $
(b) $ \frac{3}{4} \square \frac{2}{6} $
(c) $ \frac{2}{3} \square \frac{2}{4} $
(d) $ \frac{6}{6} \square \frac{3}{3} $
(e) $ \frac{5}{6} \square \frac{5}{5} $"
To do:
We have to write '$<$' or ' \( > \) ', '$=$' between the given pairs of fractions.
Solution:
(a) From the figure,
The area occupied by $\frac{1}{3}$ is greater than the area occupied by $\frac{1}{6}$
This implies,
$\frac{1}{3}>\frac{1}{6}$
Therefore,
$\frac{1}{6} < \frac{1}{3}$
(b) From the figure,
The area occupied by $\frac{3}{4}$ is greater than the area occupied by $\frac{2}{6}$
This implies,
$\frac{3}{4}>\frac{2}{6}$
(c) From the figure,
The area occupied by $\frac{2}{3}$ is greater than the area occupied by $\frac{2}{4}$
This implies,
$\frac{2}{3}>\frac{2}{4}$
(d) From the figure,
The area occupied by $\frac{6}{6}$ is equal to the area occupied by $\frac{3}{3}$
This implies,
$\frac{6}{6} =\frac{3}{3}$
(e) From the figure,
The area occupied by $\frac{5}{5}$ is greater than the area occupied by $\frac{5}{5}$
This implies,
$\frac{5}{5}>\frac{5}{6}$
Therefore,
$\frac{5}{6} < \frac{5}{5}$