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log1p() in C++ program
We are given with a variable of any type and the task is to find the result using the function log1p(). log1p() is an analytical function that takes an argument ‘a’ and also has a return value.
Syntax
double log1p (double x); Where x ranges between [-1, ?] float log1p (float x);
Return Type − This function returns a non-zero value if the argument is greater than -1 else it will return a non-numeric value.
Example
Input
a = 20.34
Output
3.06058
Input
a = 0.0
Output
0
Example
#include <cmath>
#include <iostream>
using namespace std;
int main(){
double ans = 20.34;
double temp;
temp = log1p(ans);
cout << "value of log1p(" << ans << ") is: "<<temp<< endl;
ans = 0.0;
temp = log1p(ans);
cout << "value of log1p(" << ans << ") is: "<<temp<< endl;
return 0;
}Output
value of log1p(20.34) is: 3.06058 value of log1p(0) is: 0
Updated on: 17-Apr-2020
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