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Largest Even and Odd N-digit numbers in C++
In this tutorial, we are going to write a program that finds the largest even and odd number of n digits number.
Let's see the steps to solve the problem.
- Initialise the number n.
- The largest odd number is pow(10, n) - 1.
- The largest even number is odd - 1.
Example
Let's see the code.
#include <bits/stdc++.h> using namespace std; void findEvenAndOddNumbers(int n) { int odd = pow(10, n) - 1; int even = odd - 1; cout << "Even: " << even << endl; cout << "Odd: " << odd << endl; } int main() { int n = 6; findEvenAndOddNumbers(n); return 0; }
Output
If you run the above code, then you will get the following result.
Even: 999998 Odd: 999999
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
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