How to search the minimum and the maximum element in an array using Java



Problem Description

How to search the minimum and the maximum element in an array?

Solution

This example shows how to search the minimum and maximum element in an array by using Collection.max() and Collection.min() methods of Collection class .

import java.util.Arrays;
import java.util.Collections;

public class Main {
   public static void main(String[] args) {
      Integer[] numbers = { 8, 2, 7, 1, 4, 9, 5};
      int min = (int) Collections.min(Arrays.asList(numbers));
      int max = (int) Collections.max(Arrays.asList(numbers));
      
      System.out.println("Min number: " + min);
      System.out.println("Max number: " + max);
   }
}

Result

The above code sample will produce the following result.

Min number: 1
Max number: 9

Another sample example of the minimum and the maximum element in an array.

public class HelloWorld {
   public static void main(String[] args) {
      int numbers[] = new int[]{8, 2, 7, 1, 4, 9, 5};
      int s = numbers[0];
      int l = numbers[0];
      
      for(int i = 1; i < numbers.length; i++) {
         if(numbers[i] > l)l = numbers[i];
         else if (numbers[i] < s)s = numbers[i];
      } 
      System.out.println("Largest Number is : " + l);
      System.out.println("Smallest Number is : " + s);
   }
}

The above code sample will produce the following result.

Largest Number is : 9
Smallest Number is : 1   
java_arrays.htm
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