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Java program to find Largest, Smallest, Second Largest, Second Smallest in an array
To find largest, smallest, second largest, second smallest in an array, the code is as follows -
Example
import java.util.*;
public class Demo {
public static void main(String []args){
int arr[] = {55, 10, 8, 90, 43, 87, 95, 25, 50, 12};
System.out.println("Array = "+Arrays.toString(arr));
Arrays.sort(arr);
System.out.println("Sorted Array = "+Arrays.toString(arr));
System.out.println("Smallest element = "+arr[0]);
System.out.println("2nd Smallest element = "+arr[0]);
System.out.println("Largest element = "+arr[9]);
System.out.println("2nd Largest element = "+arr[8]);
}
}Output
Array = [55, 10, 8, 90, 43, 87, 95, 25, 50, 12] Sorted Array = [8, 10, 12, 25, 43, 50, 55, 87, 90, 95] Smallest element = 8 2nd Smallest element = 8 Largest element = 95 2nd Largest element = 90
Example
Let us now see another example:
import java.util.*;
public class Demo {
public static void main(String []args){
int a;
int arr[] = {55, 10, 8, 90, 43, 87, 95, 25, 50, 12};
System.out.println("Array = "+Arrays.toString(arr));
int count = arr.length;
for (int i = 0; i < count; i++) {
for (int j = i + 1; j < count; j++) {
if (arr[i] > arr[j]) {
a = arr[i];
arr[i] = arr[j];
arr[j] = a;
}
}
}
System.out.println("Smallest: "+arr[0]);
System.out.println("Largest: "+arr[count-1]);
System.out.println("Second Smallest: "+arr[1]);
System.out.println("Second Largest: "+arr[count-2]);
}
}Output
Array = [55, 10, 8, 90, 43, 87, 95, 25, 50, 12] Smallest: 8 Largest: 95 Second Smallest: 10 Second Largest: 90
Updated on: 02-Jan-2020
3K+ Views
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