Java program to calculate sum of squares of first n natural numbers

In this article, you will learn to write a program in Java to calculate the sum of squares of first n natural numbers. This program efficiently computes the sum using a mathematical formula ?

(val * (val + 1) / 2) * (2 * val + 1) / 3

Problem Statement

Write a program in Java to calculate the sum of squares of first n natural numbers, where n is a user-defined value.

Input

 val = 8

Output

The sum of squares of first 8 natural numbers is<br>204

Steps to calculate sum of squares of first n natural numbers

Following are the steps to calculate the sum of squares of first n natural numbers ?

• First we will import the necessary class from java.io and java.util package.
• Create a method called sum_of_squares() within a class to calculate the sum of squares using the formula.
• In the main method, define the value of n (e.g., 8).
• Use the sum_of_squares() method to compute the sum and display the result.

Java program to calculate the sum of squares of first n natural numbers

To calculate the sum of squares of first n natural numbers, the Java code is as follows ?

import java.io.*;
import java.util.*;
public class Demo{
   public static int sum_of_squares(int val){
      return (val * (val + 1) / 2) * (2 * val + 1) / 3;
   }
   public static void main(String[] args){
      int val = 8;
      System.out.println("The sum of squares of first 8 natural numbers is ");
      System.out.println(sum_of_squares(val));
   }
}

Output

The sum of squares of first 8 natural numbers is
204

Code Explanation

In the above program, we will learn to calculate the sum of squares of first n natural numbers. A class named Demo contains a function named ?sum_of_squares?. This function is used to add up the first ?n? natural numbers. This returns the sum of the numbers. In the main function, a value for ?n? is defined and the function is called with this ?n? value. Relevant output is displayed on the console.