![Trending Articles on Technical and Non Technical topics](/images/trending_categories.jpeg)
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now?
Given:
If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than 5 times her actual age.
To do:
We have to find her present age.
Solution:
Let the present age of Zeba be $x$ years.
This implies,
Age of Zeba if she was 5 years younger$=x-5$ years
According to the question,
$(x-5)^2=5x+11$
$x^2-10x+25=5x+11$
$x^2-10x-5x+25-11=0$
$x^2-15x+14=0$
Solving for $x$ by factorization method, we get,
$x^2-14x-x+14=0$
$x(x-14)-1(x-14)=0$
$(x-14)(x-1)=0$
$x-14=0$ or $x-1=0$
$x=14$ or $x=1$
Zeba's age cannot be $1$ year. Therefore, the value of $x$ is $14$.
$x-5=14-5=9$
The present age of Zeba is $14$ years.
Advertisements