If \( x=a, y=b \) is the solution of the equations \( x-y=2 \) and \( x+y=4 \), then the values of \( a \) and \( b \) are, respectively
(A) 3 and 5
(B) 5 and 3
(C) 3 and 1
,b>(D) \( -1 \) and \( -3 \)
Given:
\( x=a, y=b \) is the solution of the equations \( x-y=2 \) and \( x+y=4 \).
To do:
We have to find the the values of \( a \) and \( b \).
Solution:
If $x = a$ and $y = b$ is the solution of the equations $x - y = 2$ and $x+ y = 4$, then these values must satisfy the equations.
Therefore,
$a-b=2$....(i)
$a+b=4$......(ii)
Adding (i) and (ii), we get,
$2a=6$
$a=3$
This implies,
$b=4-3=1$
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