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How to sort inner array in MongoDB?
You can achieve this with the help of aggregate framework in MongoDB. To understand it, let us create a collection with document. The query to create a collection with document is as follows:
> db.sortInnerArrayDemo.insertOne(
...
... {
... "EmployeeDetails":
... {
... "EmployeeAddress":
... {
... "EmployeeCountry":
... [
... {
... "EmployeeZipCode":1003,
... "EmployeeStreetName":"7885 Trusel Street"
... },
... {
... "EmployeeZipCode":1001,
... "EmployeeStreetName":"7390 Gonzales Drive"
... },
... {
... "EmployeeZipCode":1002,
... "EmployeeStreetName":"444 N.Myres Rd."
... }
... ]
... }
... }
... }
...
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5c6f07d3da34711ecf87a5b8")
}Display all documents from a collection with the help of find() method. The query is as follows:
> db.sortInnerArrayDemo.find().pretty();
The following is the output:
{
"_id" : ObjectId("5c6f07d3da34711ecf87a5b8"),
"EmployeeDetails" : {
"EmployeeAddress" : {
"EmployeeCountry" : [
{
"EmployeeZipCode" : 1003,
"EmployeeStreetName" : "7885 Trusel Street"
},
{
"EmployeeZipCode" : 1001,
"EmployeeStreetName" : "7390 Gonzales Drive"
},
{
"EmployeeZipCode" : 1002,
"EmployeeStreetName" : "444 N.Myres Rd."
}
]}
}
}The following is the query to sort an inner array.
Case 1: Sort order in ascending order.
The query is as follows:
> db.sortInnerArrayDemo.aggregate(
... {$unwind: '$EmployeeDetails.EmployeeAddress.EmployeeCountry'},
... {$sort: {'EmployeeDetails.EmployeeAddress.EmployeeCountry.EmployeeZipCode': 1}},
... {$group: {_id: '$_id', 'EmpCountry': {$push:
'$EmployeeDetails.EmployeeAddress.EmployeeCountry'}}},
... {$project: {'EmployeeDetails.EmployeeAddress.EmployeeCountry':
'$EmpCountry'}}).pretty();The following is the output displaying the inner array is sorted in ascending order on the basis of the EmployeeZipCode:
{
"_id" : ObjectId("5c6f07d3da34711ecf87a5b8"),
"EmployeeDetails" : {
"EmployeeAddress" : {
"EmployeeCountry" : [
{
"EmployeeZipCode" : 1001,
"EmployeeStreetName" : "7390 Gonzales Drive"
},
{
"EmployeeZipCode" : 1002,
"EmployeeStreetName" : "444 N.Myres Rd."
},
{
"EmployeeZipCode" : 1003,
"EmployeeStreetName" : "7885 Trusel Street"
}
]
}
}
}Case 2: Sort order in descending order
The query is as follows:
> db.sortInnerArrayDemo.aggregate(
... {$unwind: '$EmployeeDetails.EmployeeAddress.EmployeeCountry'},
... {$sort: {'EmployeeDetails.EmployeeAddress.EmployeeCountry.EmployeeZipCode':-1}},
... {$group: {_id: '$_id', 'EmpCountry': {$push:
'$EmployeeDetails.EmployeeAddress.EmployeeCountry'}}},
... {$project: {'EmployeeDetails.EmployeeAddress.EmployeeCountry':
'$EmpCountry'}}).pretty();The following is the output displaying the inner array is sorted in descending order on the basis of the EmployeeZipCode:
{
"_id" : ObjectId("5c6f07d3da34711ecf87a5b8"),
"EmployeeDetails" : {
"EmployeeAddress" : {
"EmployeeCountry" : [
{
"EmployeeZipCode" : 1003,
"EmployeeStreetName" : "7885 Trusel Street"
},
{
"EmployeeZipCode" : 1002,
"EmployeeStreetName" : "444 N.Myres Rd."
},
{
"EmployeeZipCode" : 1001,
"EmployeeStreetName" : "7390 Gonzales Drive"
}
]
}
}
}
Updated on: 30-Jul-2019
3K+ Views
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