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How to get the ownership control details of an S3 bucket using Boto3 and AWS Client?
Problem Statement − Use boto3 library in Python to get ownership control detail of a S3 bucket.
For example, find the ownership control detail of Bucket_1 in S3.
Approach/Algorithm to solve this problem
Step 1 − Import boto3 and botocore exceptions to handle exceptions.
Step 2 − Use bucket_name as the parameter in the function.
Step 3 − Create an AWS session using boto3 library.
Step 4 − Create an AWS client for S3.
Step 5 − Now use the function get_bucket_ownership_controls and pass the bucket name.
Step 6 − It returns the dictionary containing the details about S3.
Step 7 − Handle the generic exception if something went wrong while deleting the file.
Example
Use the following code to get ownership detail of a bucket −
import boto3 from botocore.exceptions import ClientError def get_bucket_ownership_control_of_s3(bucket_name): session = boto3.session.Session() s3_client = session.client('s3') try: result = s3_client.get_bucket_ownership_controls(Bucket=bucket_name,) except ClientError as e: raise Exception( "boto3 client error in get_bucket_ownership_control_of_s3: " + e.__str__()) except Exception as e: raise Exception( "Unexpected error in get_bucket_ownership_control_of_s3: " + e.__str__()) return result print(get_bucket_ownership_control_of_s3("Bucket_1"))
Output
{ 'OwnershipControls': { 'Rules': [ { 'ObjectOwnership': 'BucketOwnerPreferred'|'ObjectWriter' }, ] } }
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