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How to get all elements of a List that match the conditions specified by the predicate in C#?
To get all elements of a List that match the conditions specified by the predicate, the code is as follows −
Example
using System; using System.Collections.Generic; public class Demo { private static bool demo(int i) { return ((i % 3) == 0); } public static void Main(String[] args) { List<int> list = new List<int>(); list.Add(9); list.Add(15); list.Add(20); list.Add(40); list.Add(50); list.Add(60); Console.WriteLine("List elements..."); foreach (int i in list) { Console.WriteLine(i); } Console.WriteLine(" "); List<int> res = new List<int>(list.FindAll(demo)); Console.WriteLine("List that match the conditions..."); foreach (int i in res) { Console.WriteLine(i); } } }
Output
This will produce the following output −
List elements... 9 15 20 40 50 60 List that match the conditions... 9 15 60
Example
Let us see another example −
using System; using System.Collections.Generic; public class Demo { private static bool demo(int i) { return ((i % 100) == 5); } public static void Main(String[] args) { List<int> list = new List<int>(); list.Add(900); list.Add(1500); list.Add(250); list.Add(405); Console.WriteLine("List elements..."); foreach (int i in list) { Console.WriteLine(i); } Console.WriteLine(" "); List<int> res = new List<int>(list.FindAll(demo)); Console.WriteLine("List that match the conditions..."); foreach (int i in res) { Console.WriteLine(i); } } }
Output
This will produce the following output −
List elements... 900 1500 250 405 List that match the conditions... 405
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