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How to find the sum of rows of a column based on multiple columns in R data frame?
To find the sum of rows of a column based on multiple columns in R data frame, we can follow the below steps −
First of all, create a data frame.
Then, use aggregate function to find the sum of rows of a column based on multiple columns.
Example
Create the data frame
Let’s create a data frame as shown below −
Grp1<-sample(LETTERS[1:4],25,replace=TRUE)
Grp2<-sample(letters[1:4],25,replace=TRUE)
Grp3<-sample(c("A-1","B-2","C-3"),25,replace=TRUE)
DV<-sample(1:50,25)
df<-data.frame(Grp1,Grp2,Grp3,DV)
dfOutput
On executing, the above script generates the below output(this output will vary on your system due to randomization) −
Grp1 Grp2 Grp3 DV 1 D b C-3 35 2 D c B-2 4 3 A a C-3 45 4 A b C-3 7 5 C b C-3 21 6 A b C-3 31 7 A c B-2 37 8 A b C-3 5 9 D b B-2 36 10 B d A-1 41 11 B c C-3 3 12 B b C-3 14 13 A b C-3 27 14 D b B-2 15 15 B d C-3 47 16 B c C-3 18 17 C a C-3 6 18 A b B-2 10 19 A c A-1 49 20 A d C-3 16 21 A a C-3 40 22 D b B-2 29 23 A c B-2 17 24 D b A-1 19 25 B c B-2 50
Find the sum of rows of a column based on multiple columns
Using aggregate function to find the sum of rows of column DV based on columns Grp1, Grp2, and Grp3 as shown below −
Grp1<-sample(LETTERS[1:4],25,replace=TRUE)
Grp2<-sample(letters[1:4],25,replace=TRUE)
Grp3<-sample(c("A-1","B-2","C-3"),25,replace=TRUE)
DV<-sample(1:50,25)
df<-data.frame(Grp1,Grp2,Grp3,DV)
aggregate(DV~Grp1+Grp2+Grp3,data=df,FUN=sum)Output
Grp1 Grp2 Grp3 DV 1 D b A-1 19 2 A c A-1 49 3 B d A-1 41 4 A b B-2 10 5 D b B-2 80 6 A c B-2 54 7 B c B-2 50 8 D c B-2 4 9 A a C-3 85 10 C a C-3 6 11 A b C-3 70 12 B b C-3 14 13 C b C-3 21 14 D b C-3 35 15 B c C-3 21 16 A d C-3 16 17 B d C-3 47
Updated on: 08-Nov-2021
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