How to find all records which are NOT in the set array with MySQL?

For this, you can use NOT IN() function.

Let us first create a table −

mysql> create table DemoTable718 (
   Id int,
   FirstName varchar(100),
   Age int
);
Query OK, 0 rows affected (0.59 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable718 values(101,'Chris',26);
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable718 values(102,'Robert',24);
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable718 values(103,'David',27);
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable718 values(104,'Mike',28);
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable718 values(105,'Sam',23);
Query OK, 1 row affected (0.14 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable718;

This will produce the following output -

+------+-----------+------+
| Id   | FirstName | Age  |
+------+-----------+------+
| 101  | Chris     | 26   |
| 102  | Robert    | 24   |
| 103  | David     | 27   |
| 104  | Mike      | 28   |
| 105  | Sam       | 23   |
+------+-----------+------+
5 rows in set (0.00 sec)

Here is the query to find all records which are NOT in the set array −

mysql> select *from DemoTable718 where Id NOT IN('101','103','104');

This will produce the following output -

+------+-----------+------+
| Id   | FirstName | Age  |
+------+-----------+------+
| 102  | Robert    | 24   |
| 105  | Sam       | 23   |
+------+-----------+------+
2 rows in set (0.00 sec)